Variable intConst

int: Simple.Parser<number> = ...

Parse integers.

Remarks

Example

Behavior

By default it only parsers non-negative integers

    run(int("1"))    // => Ok(1)
    run(int("1234")) // => Ok(1234)
    run(int("-789")) // => Err(...)
    run(int("0123")) // => Err(...)
    run(int("1.34")) // => Err(...)
    run(int("1e31")) // => Err(...)
    run(int("123a")) // => Err(...)
    run(int("0x1A")) // => Err(...)

If you want to handle a leading + or - you should do it with a custom parser like this:

    const myInt: Parser<number> = oneOf(
      succeed((n: number) => n * -1)
        .skip(symbol("-"))
        .apply(int),
      int
    );

Note: If you want a parser for both Int and Float literals, check out number below. It will be faster than using oneOf to combining int and float yourself.

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