Function many1

Similar to many, apply a parser repeatedly until it fails, but it requires at least one item to succeed.

Example

   // This parser parses an int and then all of the spaces after it.
   const int = number({ int: (n) => n }).skip(spaces);
   // We then repeat that parser zero or more times.
   const ints: Parser<number[]> = many(int);

   ints.run("1 2 3")
   // => Ok([1, 2, 3])

   ints.run("")
   // => Err ...

Remarks

You can think of it like this:

  const many1 = (parseItem) =>
     many(parseItem).andThen((items) =>
          items.length === 0 ? problem("Need to succeed at least once!") : succeed(items)
        );